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軟件設(shè)計(jì)師每日一練試題(2026/2/7)

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軟件設(shè)計(jì)師每日一練試題內(nèi)容(2026/2/7)

  • 試題1

    三總線結(jié)構(gòu)的計(jì)算機(jī)總線系統(tǒng)由( )組成。
    A.CPU總線、內(nèi)存總線和IO總線
    B.?dāng)?shù)據(jù)總線、地址總線和控制總線
    C.系統(tǒng)總線、內(nèi)部總線和外部總線
    D.串行總線、并行總線和PCI總線

    查看答案

    試題參考答案:B

    試題解析與討論:www.fsoyn.com/exam/ExamDay.aspx?t1=4&day=2026/2/7

  • 試題2

    某文件管理系統(tǒng)采用位示圖(bitmap)來記錄磁盤的使用情況,若計(jì)算機(jī)系統(tǒng)的字長為64位,磁盤容量為512GB,物理塊的大小為4MB,那么位示圖的大小為( )個(gè)字.
    A.1024
    B.2048
    C.4096
    D.9600

    查看答案

    試題參考答案:B

    試題解析與討論:www.fsoyn.com/exam/ExamDay.aspx?t1=4&day=2026/2/7

  • 試題3

    已知數(shù)據(jù)信息為 16 位,最少應(yīng)附加( )位校驗(yàn)位,以實(shí)現(xiàn)海明碼糾錯(cuò)。
    A.3
    B.4
    C.5
    D.6

    查看答案

    試題參考答案:C

    試題解析與討論:www.fsoyn.com/exam/ExamDay.aspx?t1=4&day=2026/2/7

  • 試題4

    已知樹T的度為4,且度為4的結(jié)點(diǎn)數(shù)為7個(gè)、度為3的結(jié)點(diǎn)數(shù)5個(gè)、度為2的結(jié)點(diǎn)數(shù)為8個(gè)、度為1的結(jié)點(diǎn)數(shù)為10個(gè),那么T的葉子結(jié)點(diǎn)個(gè)數(shù)為( )。(注:樹中節(jié)點(diǎn)個(gè)數(shù)稱為結(jié)點(diǎn)的度,結(jié)點(diǎn)的度中的最大值稱為樹的度。
    A.30
    B.35
    C.40
    D.49

    查看答案

    試題參考答案:C

    試題解析與討論:www.fsoyn.com/exam/ExamDay.aspx?t1=4&day=2026/2/7

  • 試題5

    由某上下文無關(guān)文法 M[S]推導(dǎo)出某句子的分析樹如下圖所示,則錯(cuò)誤的敘述是( )

    A、該文法推導(dǎo)出的句子必須以“a”開頭
    B、acabcbdcc 是該文法推導(dǎo)出的一個(gè)句子
    C、“S->aAcB”是該文法的終結(jié)符號(hào)集
    D、a、b、c、d 屬于該文法的終結(jié)符號(hào)集

    查看答案

    試題參考答案:A

    試題解析與討論:www.fsoyn.com/exam/ExamDay.aspx?t1=4&day=2026/2/7

  • 試題6

    下圖所示平衡二叉樹(樹中任一結(jié)點(diǎn)的左右子樹高度之差不超過1)中,結(jié)點(diǎn)A的右子樹AR高度為h,結(jié)點(diǎn)B的左子樹BL高度為h,結(jié)點(diǎn)C的左子樹CL、右子樹CR高度都為h-1。若在CR中插入一個(gè)結(jié)點(diǎn)并使得CR的高度增加1,則該二叉樹 ( ) 。

    A、以B為根的子二叉樹變?yōu)椴黄胶?
    B、以C為根的子二叉樹變?yōu)椴黄胶?
    C、以A為根的子二叉樹變?yōu)椴黄胶?
    D、仍然是平衡二叉樹

    查看答案

    試題參考答案:C

    試題解析與討論:www.fsoyn.com/exam/ExamDay.aspx?t1=4&day=2026/2/7

  • 試題7

    Object-oriented  analysis  (OOA)  is  a  semiformal  specification  technique  for  the object-oriented  paradigm.  Object-oriented  analysis  consists  of  three  steps.  The  first  step  is(1).  It  determines  how  the  various  results  are  computed  by  the  product  and  presents  this information in the form of a  (2)  and associated scenarios. The second is  (3)  , which determines the classes and their attributes, then determines the interrelationships and interaction among the classes. The  last step is  (4)  ,  which determines  the  actions  performed  by or to each class or subclass and presents this information in the form of  (5)  .
    (1)A、use-case modeling
    B、class modeling
    C、dynamic modeling
    D、behavioral modeling
    (2)A、collaboration diagram
    B、sequence diagram
    C、use-case diagram
    D、activity diagram
    (3)A、use-case modeling
    B、class modeling
    C、dynamic modeling
    D、behavioral modeling
    (4)A、use-case modeling
    B、class modeling
    C、dynamic modeling
    D、behavioral modeling
    (5)A、activity diagram
    B、component diagram
    C、sequence diagram
    D、state diagram

    查看答案

    試題參考答案:A、C、B、C、D

    試題解析與討論:www.fsoyn.com/exam/ExamDay.aspx?t1=4&day=2026/2/7

  • 試題8

    Low-code and no code software development solutions have emerged as viable and convenient alternatives to the traditional development process.
    Low-code is a rapid application development (RAD) approach that enables automated code generation through(71) building blocks like drag-and-drop and pull-down menu interfaces.This (72) allows low-code users to focus on the diferentiator rather than the common denominator of programming. Low-code is a balanced middle ground between manual coding and no-code as its users can still add code over auto-generated code.While in low-code there is some hand holding done by developers in the form of scripting or manual coding, no-code has a completely (73) approach, with 100% dependence on visual tools.
    A low-code application platform (LCAP)——also called a low-code development platform (LCDP)——contains an integrated development environment (IDE) with (74) features like APIs, code templates, reusable plug-in modules and graphical connectors to automate a significant percentage of the application development process.LCAPs are typically available as cloud-based Platform-as-a-Service (PaaS) solutions.
    A low-code platform works on the principle or lowering complexity by using visual to and techniques like  process modeling. where users employ visual tools to define workflobusiness rules, user interfaces and the like.Behind the scenes, the complete workflovautomatically converted into code. LCAPs are used predominantly by professional developeautomate the generic aspects of coding to redirect effort on the last mile of (75).
    (71)
    A.visual
    B.component-based
    C.object-oriented
    D.structural
    (72)
    A.block
    B.a(chǎn)utomation
    C.function
    D.method
    (73)
    A.modern
    B.hands-off
    C.generic
    D.labor-free
    (74)
    A.reusable
    B.built-in
    C.existed
    D.well-known
    (75)
    A.delivery
    B.a(chǎn)utomation
    C.development
    D.success

    查看答案

    試題參考答案:A、B、B、B、C

    試題解析與討論:www.fsoyn.com/exam/ExamDay.aspx?t1=4&day=2026/2/7

  • 試題9

    可以構(gòu)造出下圖所示二叉排序樹(二叉檢索樹、二叉查找樹)的關(guān)鍵碼序列是( )。

    A.10 13 17 19 23 27 31 40 65 91
    B.23 40 91 17 19 10 31 65 27 13
    C.23 19 40 27 17 13 10 91 65 31
    D.27 31 40 65 91 13 10 17 23 19

    查看答案

    試題參考答案:B

    試題解析與討論:www.fsoyn.com/exam/ExamDay.aspx?t1=4&day=2026/2/7

  • 試題10

    在以階段劃分的編譯過程中,判斷程序語句的形式是否正確屬于( )階段的工作。
    A.詞法分析
    B.語法分析
    C.語義分析
    D.代碼生成

    查看答案

    試題參考答案:B

    試題解析與討論:www.fsoyn.com/exam/ExamDay.aspx?t1=4&day=2026/2/7

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